Java += operator

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Java += operator

Anonymous User · Accepted Answer

"As always with these questions, the JLS holds the answer. In this case &#167;15.26.2 Compound Assignment Operators. An extract:A compound assignment expression of the form E1 op= E2 is equivalent to E1 = (T)((E1) op (E2)), where T is the type of E1, except that E1 is evaluated only once.An example cited from &#167;15.26.2[...] the following code is correct:short x = 3;x += 4.6;and results in x having the value 7 because it is equivalent to:short x = 3;x = (short)(x + 4.6);In other words, your assumption is correct."

Anonymous User · Answer

As always with these questions, the JLS holds the answer. In this case §15.26.2 Compound Assignment Operators. An extract:

A compound assignment expression of the form E1 op= E2 is equivalent to E1 = (T)((E1) op (E2)), where T is the type of E1, except that E1 is evaluated only once.

An example cited from §15.26.2

[...] the following code is correct:

short x = 3;

x += 4.6;

and results in x having the value 7 because it is equivalent to:

short x = 3;

x = (short)(x + 4.6);

In other words, your assumption is correct.

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Java += operator

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