.CHANGE EVENT NOT WORK AS DYNAMIC AS EXPECTED

Monaj Singh

Total Post:41

Points:287
Posted by  Monaj Singh
 816  View(s)
Ratings:
Rate this:

I'm new to javascript, I'm using jquery, this is my html with php code:

<form action="" method="POST" enctype="multipart/form-data">

    <h1>Quantity 1</h1>

    <input id="btn1" type="number" name="cantpag" value="<?php echo $cp; ?>">

 

    <h1>Quantity 2</h1>

    <input id="btn2" type="number" name="cantreinv" value="<?php echo $cr; ?>">

 

    <input type="submit">

</form>

Here is my JS:

<script>

$(document).ready(function(){

    $(document).on('change','#btn1',function(){

        alert('works');

    });

});</script>

When I change the value of "#btn1", nothing happens immediately, instead, I must press tab or somwhere else to have the alert show up. Is there any way for this to be instant, as in, just adding or removing a number from the input field triggers the alert?

  1. Kamlakar Singh

    Post:194

    Points:1396
    Re: .change event not work as dynamic as expected

    $(document).ready(function(){

            $(document).on('input','#btn1',function(){

                alert('works');

            });

        });

    <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

    <form action="" method="POST" enctype="multipart/form-data">

        <h1>Quantity 1</h1>

        <input id="btn1" type="number" name="cantpag" value="<?php echo $cp; ?>">

     

        <h1>Quantity 2</h1>

        <input id="btn2" type="number" name="cantreinv" value="<?php echo $cr; ?>">

     

        <input type="submit">

    </form>

Answer

NEWSLETTER

Enter your email address here always to be updated. We promise not to spam!