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char char = int? Why?

Royce Roy211306-Jun-2013
Hi All,

Why is adding two char in C# results to an int type?

For example, when I do this:

var pr = 'R' + 'G' + 'B' + 'Y' + 'P';
the pr variable becomes an int type. I expect it to be a string type with a value of "RGBYP".

Why is C# designed like this? Wasn't the default implementation of adding two chars should be resulting to a string that concatenates the chars, not int?

Thanks in advance. 

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Updated on 06-Jun-2013
Royce Roy

Royce Roy

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1 Answers

AVADHESH PATEL

AVADHESH PATEL

06-Jun-2013
Hi,

You can simply convert the first of your chars to a string, to outwit your compiler:

var pr = 'R'.ToString() + 'G' + 'B' + 'Y' + 'P';

You could also define a char array and then use the string constructor:

char[] letters = { 'R', 'G', 'B','Y', 'P' };

string alphabet = new string(letters);
If you want to print out a character solely, you always have to convert it to a string, to get its text representation:

 var foo1 = 'F';
 MessageBox.Show(foo1.ToString());

Thanks in advance.

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