I have used the code first approach to design the database as follows:
Then create the database context class in the model:
After creating the context class create a HomeController and inside that create action Index(). Then right click on the Index() action and create a view Index.
Then create WebGrid in the view Index as follows and set the ajaxUpdateContainerId property of WebGrid with the id of the division containing the web grid.
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Loading view with AJAX
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Anonymous User
05-Aug-2017