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Goti Bandu

Total Post:119

Points:835
Posted on    December-27-2013 6:43 AM

 C# C# 
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Is there an efficient method of converting an integer into the written numbers, for example:

string Written = IntegerToWritten(21);

would return "Twenty One".

Is there any way of doing this that doesn't involve a massive look-up table?


Alex Leblois
Alex Leblois

Total Post:67

Points:471
Posted on    December-27-2013 7:07 AM

Hi Goti,

You can do like this:

public static class HumanFriendlyInteger

{

    static string[] ones = new string[] { "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" };

    static string[] teens = new string[] { "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" };

    static string[] tens = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };

    static string[] thousandsGroups = { "", " Thousand", " Million", " Billion" };

    private static string FriendlyInteger(int n, string leftDigits, int thousands)

    {

        if (n == 0)

        {

            return leftDigits;

        }

        string friendlyInt = leftDigits;

        if (friendlyInt.Length > 0)

        {

            friendlyInt += " ";

        }

        if (n < 10)

        {

            friendlyInt += ones[n];

        }

        else if (n < 20)

        {

            friendlyInt += teens[n - 10];

        }

        else if (n < 100)

        {

            friendlyInt += FriendlyInteger(n % 10, tens[n / 10 - 2], 0);

        }

        else if (n < 1000)

        {

            friendlyInt += FriendlyInteger(n % 100, (ones[n / 100] + " Hundred"), 0);

        }

        else

        {

            friendlyInt += FriendlyInteger(n % 1000, FriendlyInteger(n / 1000, "", thousands+1), 0);

        }

        return friendlyInt + thousandsGroups[thousands];

    }

    public static string IntegerToWritten(int n)

    {

        if (n == 0)

        {

            return "Zero";

        }

        else if (n < 0)

        {

            return "Negative " + IntegerToWritten(-n);

        }

        return FriendlyInteger(n, "", 0);

    }

}


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