CONVERT INTEGERS TO WRITTEN NUMBERS

Goti Bandu

Total Post:119

Points:835
Posted by  Goti Bandu
C# 
C#
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Is there an efficient method of converting an integer into the written numbers, for example:

string Written = IntegerToWritten(21);
would return "Twenty One".
Is there any way of doing this that doesn't involve a massive look-up table?
  1. Alex Leblois

    Post:67

    Points:471
    Re: Convert integers to written numbers

    Hi Goti,


    You can do like this:
    public static class HumanFriendlyInteger
    {
        static string[] ones = new string[] { "", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine" };
        static string[] teens = new string[] { "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen" };
        static string[] tens = new string[] { "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety" };
        static string[] thousandsGroups = { "", " Thousand", " Million", " Billion" };
        private static string FriendlyInteger(int n, string leftDigits, int thousands)
        {
            if (n == 0)
            {
                return leftDigits;
            }
            string friendlyInt = leftDigits;
            if (friendlyInt.Length > 0)
            {
                friendlyInt += " ";
            }
            if (n < 10)
            {
                friendlyInt += ones[n];
            }
            else if (n < 20)
            {
                friendlyInt += teens[n - 10];
            }
            else if (n < 100)
            {
                friendlyInt += FriendlyInteger(n % 10, tens[n / 10 - 2], 0);
            }
            else if (n < 1000)
            {
                friendlyInt += FriendlyInteger(n % 100, (ones[n / 100] + " Hundred"), 0);
            }
            else
            {
                friendlyInt += FriendlyInteger(n % 1000, FriendlyInteger(n / 1000, "", thousands+1), 0);
            }
            return friendlyInt + thousandsGroups[thousands];
        }
        public static string IntegerToWritten(int n)
        {
            if (n == 0)
            {
                return "Zero";
            }
            else if (n < 0)
            {
                return "Negative " + IntegerToWritten(-n);
            }
            return FriendlyInteger(n, "", 0);
        }
    }

      Modified On Apr-04-2018 01:10:16 AM

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