Java pattern for [j-*]

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Java 
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Please help me  with the pattern matching. I want to build a pattern which will match the word starting withj- or c- in the following in a string (Say for example)

[j-test] is a [c-test]'s name with [foo] and [bar]

The pattern needs to find [j-test] and [c-test] (brackets inclusive).

What I have tried so far?

String template = "[j-test] is a [c-test]'s name with [foo] and [bar]";

Pattern patt = Pattern.compile("\\[[*[j|c]\\-\\w\\-\\+\\d]+\\]");
Matcher m = patt.matcher(template);
while (m.find()) {
    System.out.println(m.group());
}


And its giving output like

[j-test]

[c-test]
[dood]
[bar]

which is wrong. Please help me, thanks for your time on this thread.

  1. Post:19

    Points:133
    Re: Java pattern for [j-*]

    Inside a character class, you don't need to use alternation to match j or c. Character class itself means, match any single character from the ones inside it. So, [jc] itself will match either j or c.

    Also, you don't need to match the pattern that is after j- or c-, as you are not bothered about them, as far as they start with j- or c-.

    Simply use this pattern:

    Pattern patt = Pattern.compile("\\[[jc]-[^\\]]*\\]");

    To explain:


    Pattern patt = Pattern.compile("(?x)      "   // Embedded flag for Pattern.COMMENT
    
                                 + "\\[ " // Match starting `[`
                                 + " [jc] " // Match j or c
                                 + " - " // then a hyphen
                                 + " [^ " // A negated character class
                                 + " \\]" // Match any character except ]
                                 + " ]* " // 0 or more times
                                 + "\\] "); // till the closing ]

    Using (?x) flag in the regex,  ignores the whitespaces. It is often helpful, to write readable regexes.

      Modified On Apr-03-2018 04:48:22 AM

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