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Home Forums How to create a timeout using a Promise to cancel a long-running asynchronous operation? – MindStick
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1 Answers

Aryan Kumar
Aryan Kumar 26 Sep 2023
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To create a timeout using a promise to cancel a long-running asynchronous operation, you can use the Promise.race method in JavaScript. Here's a simple example:

function runWithTimeout(asyncFunction, timeout) {
  return Promise.race([
    asyncFunction(),
    new Promise((_, reject) => {
      setTimeout(() => {
        reject(new Error('Operation timed out'));
      }, timeout);
    }),
  ]);
}

// Example usage:
const longRunningTask = () => {
  return new Promise((resolve) => {
    // Simulate a long-running operation
    setTimeout(() => {
      resolve('Operation completed');
    }, 5000); // This operation takes 5 seconds
  });
};

const timeoutMilliseconds = 3000; // Set a timeout of 3 seconds

runWithTimeout(longRunningTask, timeoutMilliseconds)
  .then((result) => {
    console.log(result);
  })
  .catch((error) => {
    console.error(error.message); // Handle the timeout error
  });

In this example:

  • The runWithTimeout function takes two arguments: asyncFunction, which is the asynchronous operation you want to run, and timeout, which is the maximum time allowed for the operation to complete.
  • Inside runWithTimeout, we create a new Promise that rejects with a timeout error after the specified timeout duration if the asynchronous operation does not complete in time.
  • We use Promise.race to race the original asyncFunction and the timeout Promise. Whichever resolves or rejects first will determine the outcome of the overall promise.
  • If the asyncFunction completes within the specified time, the then block will execute, and you can handle the result.
  • If the asyncFunction takes longer than the specified timeout, the catch block will execute with a timeout error message.

This approach allows you to cancel or timeout long-running asynchronous operations gracefully.

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