How to use a lambda expression in Enumerable.Distinct()?

Question

Aryan Kumar · Answer

Sure, I can help you with that.
To use a lambda expression in Enumerable.Distinct(), you need to pass the lambda expression as the predicate parameter to the
Distinct() method. The predicate parameter is a function that takes two elements of the sequence as its parameters and returns a boolean value. The
Distinct() method will return a sequence that contains only the elements of the original sequence for which the predicate returns
true.
Here is an example of how to use a lambda expression in Enumerable.Distinct():
C#
using System;
using System.Collections.Generic;
namespace DistinctLambdaExpression
{
    public class Program
    {
        public static void Main(string[] args)
        {
            // Create a list of numbers.
            Listandlt;int> numbers = new Listandlt;int>();
            numbers.Add(1);
            numbers.Add(2);
            numbers.Add(3);
            numbers.Add(1);
            numbers.Add(2);
            // Use a lambda expression to remove duplicate numbers.
            Listandlt;int> distinctNumbers = numbers.Distinct((x, y) => x != y);
            // Print the distinct numbers.
            foreach (int number in distinctNumbers)
            {
                Console.WriteLine(number);
            }
        }
    }
}
In this example, the lambda expression takes two integers as its parameters and returns a boolean value. The lambda expression returns
true if the two integers are not equal, and false if the two integers are equal. The
Distinct() method will return a sequence that contains only the elements of the original sequence for which the predicate returns
true.

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How to use a lambda expression in Enumerable.Distinct()?

Steilla Mitchel

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