how to catch multiple exceptions at once?

Question

Aryan Kumar · Answer

Sure, here is how you can catch multiple exceptions at once:
Java
try {
  // Code that might throw exceptions
} catch (ExceptionType1 | ExceptionType2 | ExceptionType3 e) {
  // Handle exceptions of type ExceptionType1, ExceptionType2, or ExceptionType3
}
For example, the following code will catch ArithmeticException, 
NullPointerException, and ArrayIndexOutOfBoundsException exceptions:
Java
try {
  int x = 10 / 0;
} catch (ArithmeticException | NullPointerException | ArrayIndexOutOfBoundsException e) {
  System.out.println("An exception occurred: " + e.getMessage());
}
When multiple exceptions are caught in a single catch block, the order of the exceptions is important. The first exception that is thrown will be the one that is handled by the catch block. If the catch block does not handle the exception, it will be rethrown.
It is important to note that if a catch block catches a more general exception type, it will also catch all of the more specific exception types. For example, the following code will catch both
ArithmeticException and NullPointerException exceptions:
Java
try {
  int x = 10 / 0;
} catch (Exception e) {
  System.out.println("An exception occurred: " + e.getMessage());
}
This is because Exception is a more general exception type than 
ArithmeticException and NullPointerException.
Here are some additional things to keep in mind when catching multiple exceptions:
The catch parameter is implicitly final, which means that you cannot assign any values to it.Catching multiple exceptions can reduce code duplication and improve the efficiency of your program.It is important to order the exceptions in the catch block correctly.Catching a more general exception type can also catch more specific exception types.

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how to catch multiple exceptions at once?

Revati S Misra

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