What is the command that is used to exit in Node.js?

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Aryan Kumar · Answer

In Node.js, the command to exit a program is process.exit([code]). The process.exit() method exits the current Node.js process with an optional exit code.

The code parameter is an integer that represents the exit code. The exit code can be used to indicate the reason for the process exit. A value of 0 indicates successful termination, while non-zero values indicate an error or other non-successful exit.

Here's an example of how to use process.exit() to exit a Node.js program:

// app.js
console.log('Starting program...');
if (process.argv[2] === 'exit') {
 console.log('Exiting program...');
 process.exit();
}
console.log('Continuing program...');

In this example, we use process.argv to check if the command line argument is "exit". If it is, we print a message and exit the program using process.exit(). If it isn't, we continue with the rest of the program.

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What is the command that is used to exit in Node.js?

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