Chnaged Data

Hello this is Gulshan Negi

Well, here is the program that you should try.

import java.util.Scanner;
public class PalindromeChecker {
   public static void main(String[] args) {
       Scanner input = new Scanner(System.in);
       System.out.print("Enter a string: ");
       String str = input.nextLine();
       if(isPalindrome(str)) {
           System.out.println(str + " is a palindrome");
       } else {
           System.out.println(str + " is not a palindrome");
       }
   }
   public static boolean isPalindrome(String str) {
       String reverseStr = new StringBuilder(str).reverse().toString();
       return str.equalsIgnoreCase(reverseStr);
   }
}

I hope it will help you.

Thanks      

Given below is a code to check whether a given string is palindrome or not.

class palindrome
{
    public static void main(String args[])
    {
        String word = "Malayalam";

        int flag=1;
        int n = word.length();
        String rev = "";
        for(int i = n-1; i >= 0; i--)
        {
        	//reversing the string
        	rev += word.charAt(i);
        }

        for(int i = 0; i < n; i++)
        {
            if(rev.charAt(i) != word.charAt(i))
            {
                //checking if reversed string and given string are equal
                if(rev.charAt(i) - word.charAt(i) == 32 || word.charAt(i) - rev.charAt(i)== 32)
                {
                    flag=1;
                }
                else
                {   
                	flag=0;
                	break;
                }
            }
        }

        if(flag==1)
        {
            System.out.println(word+" is a palindrome.");
        }
         else
            System.out.println(word+" is not a palindrome.");
    }
}
OUTPUT:
Malayalam is a palindrome.

Here, we reverse the given string and store it in another string object. Then, we check each letter of both the given string and reversed string. If the characters are not the same at any point, we set flag = 0 and breaks from the loop.