C# Program to find all the divisible numbers by 7 which are Less than 100

Question

Aryan Kumar · Answer

Sure, here is a C# program to find all the divisible numbers by 7 which are less than 100:
C#
using System;
public class DivisibleBy7 {
    public static void Main(string[] args) {
        Console.WriteLine("Divisible numbers by 7 which are less than 100:");
        for (int i = 1; i andlt; 100; i++) {
            if (i % 7 == 0) {
                Console.WriteLine(i);
            }
        }
    }
}
This program uses a for loop to iterate through the numbers 1 to 99. It then uses the modulus operator (%) to check if each number is divisible by 7. If the number is divisible by 7, it is printed to the console. When you run this program, it will output all the divisible numbers by 7 which are less than 100.
Here is an example of how the program would work:
Code snippet
Divisible numbers by 7 which are less than 100:
7
14
21
28
35
42
49
56
63
70
77
84
91

Sanjay Goenka · Answer

Sure, here is an example C# program that finds all the divisible numbers by 7 which are less than 100:
arduinoCopy code
using System;
class Program
{
    static void Main(string[] args)
    {
        Console.WriteLine("Divisible numbers by 7 which are less than 100:");
        for (int i = 1; i andlt; 100; i++)
        {
            if (i % 7 == 0)
            {
                Console.WriteLine(i);
            }
        }
        Console.ReadLine();
    }
}
This program uses a for loop to iterate through the numbers 1 to 99 and checks if each number is divisible by 7 using the modulus operator (%). If the number is divisible by 7, it is printed to the console.
When you run this program, it will output all the divisible numbers by 7 which are less than 100.

Gaurika C · Answer

The following code can be employed to get multiples of 7 lesser than 100. The % operator gives the remainder for 2 values. The logic depicts that if the remainder is 0, that means the number is completely divisible by 7. The for loop continues to be executed till the number is greater than 1 and lesser than 100. Note that the sign is not andlt;= which depicts that 100 is not included in the range of numbers to be verified for divisibility. i++ refers to an increment in the value of the number to be checked for division with 7.
and 
Using System;
and 
class Program
{
and  and  static void Main(string[ ] args)
and  and  {
and  and  and  and  for (int i = 1; i andlt; 100; i++)
and  and  and  and  {
and  and  and  and  and  and  if (i % 7 == 0)
and  and  and  and  and  and  {
and  and  and  and  and  and  and  and  Console.WriteLine(i);
and  and  and  and  and  and  }
and  and  and  and  }
and  and  }
}
The output of the code would be 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98

Ashutosh Patel · Answer

This is the C# program to find divisible numbers of any specific number and below 100,
and 
using System;
namespace HelloWorld
{
  class Program
  {
    static void Main(string[] args)
    {
      int num;
      Console.WriteLine("Divided numbers by 7 are : ");
      for(int i =1; iandlt;=100; i++)
      {
       and and and and  and num = i%7; 
         if(num==0)
         {
         and and  and  Console.WriteLine(i);
         }
      }
      Console.ReadLine();
    }
  }
}
Outpt: Divided numbers by 7 are: 
7
14
21
28
35
42
49
56
63
70
77
84
91
98
and

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C# Program to find all the divisible numbers by 7 which are Less than 100

Steilla Mitchel

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