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C# Program to find all the divisible numbers by 7 which are Less than 100

Steilla Mitchel 1166 14 Feb 2023

how to find all the numbers below 100 which ara divided by 7.

c# c#javaprograms
Updated 15 Jun 2023
Steilla Mitchel
Steilla Mitchel

Student

I completed my post-graduation in 2013 in the engineering field. Engineering is the application of science and math to solve problems. Engineers figure out how things work and find practical uses for scientific discoveries. Scientists and inventors often get the credit for innovations that advance the human condition, but it is engineers who are instrumental in making those innovations available to the world. I love pet animals such as dogs, cats, etc.

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4 Answers

Aryan Kumar
Aryan Kumar 15 Jun 2023
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Sure, here is a C# program to find all the divisible numbers by 7 which are less than 100:

C#

using System;

public class DivisibleBy7 {

    public static void Main(string[] args) {
        Console.WriteLine("Divisible numbers by 7 which are less than 100:");
        for (int i = 1; i < 100; i++) {
            if (i % 7 == 0) {
                Console.WriteLine(i);
            }
        }
    }
}

This program uses a for loop to iterate through the numbers 1 to 99. It then uses the modulus operator (%) to check if each number is divisible by 7. If the number is divisible by 7, it is printed to the console. When you run this program, it will output all the divisible numbers by 7 which are less than 100.

Here is an example of how the program would work:

Code snippet

Divisible numbers by 7 which are less than 100:
7
14
21
28
35
42
49
56
63
70
77
84
91
Sanjay Goenka
Sanjay Goenka 06 Apr 2023
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Sure, here is an example C# program that finds all the divisible numbers by 7 which are less than 100:

arduinoCopy code

using System;
class Program
{
    static void Main(string[] args)
    {
        Console.WriteLine("Divisible numbers by 7 which are less than 100:");
        for (int i = 1; i < 100; i++)
        {
            if (i % 7 == 0)
            {
                Console.WriteLine(i);
            }
        }
        Console.ReadLine();
    }
}

This program uses a for loop to iterate through the numbers 1 to 99 and checks if each number is divisible by 7 using the modulus operator (%). If the number is divisible by 7, it is printed to the console.

When you run this program, it will output all the divisible numbers by 7 which are less than 100.

Gaurika C
Gaurika C 06 Apr 2023
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The following code can be employed to get multiples of 7 lesser than 100. The % operator gives the remainder for 2 values. The logic depicts that if the remainder is 0, that means the number is completely divisible by 7. The for loop continues to be executed till the number is greater than 1 and lesser than 100. Note that the sign is not <= which depicts that 100 is not included in the range of numbers to be verified for divisibility. i++ refers to an increment in the value of the number to be checked for division with 7.

Using System;

class Program

{

    static void Main(string[ ] args)

    {

        for (int i = 1; i < 100; i++)

        {

            if (i % 7 == 0)

            {

                Console.WriteLine(i);

            }

        }

    }

}

The output of the code would be 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98

Ashutosh Patel
Ashutosh Patel 15 Feb 2023
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This is the C# program to find divisible numbers of any specific number  below 100,

using System;

namespace HelloWorld
{
  class Program
  {
    static void Main(string[] args)
    {
      int num;
      Console.WriteLine("Divided numbers by 7 are : ");
      for(int i =1; i<=100; i++)
      {
             num = i%7; 
         
         if(num==0)
         {
              Console.WriteLine(i);
         }
      }
      Console.ReadLine();
    }
  }
}

Outpt: Divided numbers by 7 are: 
7
14
21
28
35
42
49
56
63
70
77
84
91
98
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