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C# Program to find all the divisible numbers by 7 which are Less than 100

Steilla Mitchel52514-Feb-2023

how to find all the numbers below 100 which ara divided by 7.

c# c#  java  programs 
Updated on 15-Jun-2023
Steilla Mitchel

Steilla Mitchel

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4 Answers

Aryan Kumar

Aryan Kumar

15-Jun-2023

Sure, here is a C# program to find all the divisible numbers by 7 which are less than 100:

C#

using System;

public class DivisibleBy7 {

    public static void Main(string[] args) {
        Console.WriteLine("Divisible numbers by 7 which are less than 100:");
        for (int i = 1; i < 100; i++) {
            if (i % 7 == 0) {
                Console.WriteLine(i);
            }
        }
    }
}

This program uses a for loop to iterate through the numbers 1 to 99. It then uses the modulus operator (%) to check if each number is divisible by 7. If the number is divisible by 7, it is printed to the console. When you run this program, it will output all the divisible numbers by 7 which are less than 100.

Here is an example of how the program would work:

Code snippet

Divisible numbers by 7 which are less than 100:
7
14
21
28
35
42
49
56
63
70
77
84
91
Sanjay Goenka

Sanjay Goenka

06-Apr-2023

Sure, here is an example C# program that finds all the divisible numbers by 7 which are less than 100:

arduinoCopy code

using System;
class Program
{
    static void Main(string[] args)
    {
        Console.WriteLine("Divisible numbers by 7 which are less than 100:");
        for (int i = 1; i < 100; i++)
        {
            if (i % 7 == 0)
            {
                Console.WriteLine(i);
            }
        }
        Console.ReadLine();
    }
}

This program uses a for loop to iterate through the numbers 1 to 99 and checks if each number is divisible by 7 using the modulus operator (%). If the number is divisible by 7, it is printed to the console.

When you run this program, it will output all the divisible numbers by 7 which are less than 100.

Gaurika C

Gaurika C

06-Apr-2023

The following code can be employed to get multiples of 7 lesser than 100. The % operator gives the remainder for 2 values. The logic depicts that if the remainder is 0, that means the number is completely divisible by 7. The for loop continues to be executed till the number is greater than 1 and lesser than 100. Note that the sign is not <= which depicts that 100 is not included in the range of numbers to be verified for divisibility. i++ refers to an increment in the value of the number to be checked for division with 7.

 

Using System;

 

class Program

{

    static void Main(string[ ] args)

    {

        for (int i = 1; i < 100; i++)

        {

            if (i % 7 == 0)

            {

                Console.WriteLine(i);

            }

        }

    }

}

The output of the code would be 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84, 91, 98

Ashutosh Patel

Ashutosh Patel

15-Feb-2023

This is the C# program to find divisible numbers of any specific number  below 100,

 

using System;

namespace HelloWorld
{
  class Program
  {
    static void Main(string[] args)
    {
      int num;
      Console.WriteLine("Divided numbers by 7 are : ");
      for(int i =1; i<=100; i++)
      {
             num = i%7; 
         
         if(num==0)
         {
              Console.WriteLine(i);
         }
      }
      Console.ReadLine();
    }
  }
}

Outpt: Divided numbers by 7 are: 
7
14
21
28
35
42
49
56
63
70
77
84
91
98

 

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