Services
Technology Web App Development Mobile App Development Windows App Development Database Development UI/UX Development Cloud Development SEO Digital Marketing Guest Posting Content Writing Artificial Intelligence Data Science ERP Development CRM Development CMS Development LMS Development Business Listing Blockchain Technology Startup Promotion AI Tools Integration
Products
Data Converter Cleaner TUC - Unit Converter Import Export Survey Manager Tweet Controller
Developer
Article Blog Forum Interview Beginner News Startup Quiz
Users
Career
Apply Job Internship
Pricing
Login Sign Up Get a Quote

forum

Home Forums Create a List that contain each Line of a File in Python – MindStick
Ask Question

Create a List that contain each Line of a File in Python

Erick Wilsom 1086 27 Oct 2022

I'm trying to open a file and create a list with each line read from the file.

   i=0

   list=[""]

   for data in file_name:

      list[i]=data.split(",")

      i+=1

   print list

But this sample code gives me an error because of the i+=1 saying that index is out of range. What's my problem here? How can I write the code in order to increment my list with every new Line in the InFile?

python pythonpython-3.x
Erick Wilsom
Ask by Erick Wilsom
Updated 19 Jun 2023

2 Answers

Tehran Noorani
Tehran Noorani 19 Jun 2023
Report Abuse 
import os

file_path = "/path/to/your/file.txt"  # Replace with the actual physical file path

if os.path.isfile(file_path):
    lines = []  # List to store each line

    # Open the file in read mode
    with open(file_path, 'r') as file:
        # Read each line and store it in the list
        for line in file:
            lines.append(line.strip())  # Use strip() to remove any leading/trailing whitespace

    # Print the list of lines
    for line in lines:
        print(line)
else:
    print("The file does not exist or the path is incorrect.")

Make sure to replace "path/to/your/file.txt" with the actual file path on your system. This code will open the file, iterate over each line, strip any leading or trailing whitespace, and append the line to the lines list. Finally, it will print each line in the list.

Aryan Kumar
Aryan Kumar 19 Jun 2023
Report Abuse

Sure, here is how you can create a list that contains each line of a file in Python:

Python

def create_list_of_lines(filename):
  """
  Creates a list that contains each line of a file.

  Args:
    filename: The name of the file to read.

  Returns:
    A list of the lines in the file.
  """

  with open(filename, 'r') as file:
    lines = file.readlines()

  return lines


if __name__ == "__main__":
  filename = 'my_file.txt'
  lines = create_list_of_lines(filename)
  for line in lines:
    print(line)

This code first defines a function called create_list_of_lines(). The function takes a filename as input and returns a list of the lines in the file. The function works by first opening the file in read mode. Then, the function reads the lines of the file and stores them in a list. Finally, the function returns the list.

The code then defines a variable called filename and assigns it the value of the file to read. The code then calls the create_list_of_lines() function and stores the result in a variable called lines. Finally, the code iterates through the list of lines and prints each line to the console.

To run the code, you can save it as a Python file and then run it from the command line. For example, if you save the code as create_list_of_lines.py, you can run it by typing the following command into the command line:

Code snippet

python create_list_of_lines.py

This will print the lines of the file to the console.

MindStick Training
Markdown for AI

A clean, structured version of this page for AI assistants and LLMs.

Open .md