Im woundering if its possible to get .outerHeight() of
element only if its is visible
I currently have
var $viewItem = $('.test').find('.item');
var viewItemHeight = $viewItem.outerHeight(true);
The problem is $viewItem
Will return two elements at a time, one will be hidden. If
is possible to test and only get the height of the visible one ?
What about the visible selector?
var $viewItem = $('.test').find('.item:visible');
var viewItemHeight = $viewItem.outerHeight(true);