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Anubhav Sharma
Anubhav Sharma

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The Anubhav portal was launched in March 2015 at the behest of the Hon'ble Prime Minister for retiring government officials to leave a record of their experiences while in Govt service .

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1 Answers

Anubhav Sharma
Anubhav Sharma 24 Apr 2025
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Problem Statement

Given a sentence like:

sentence = "hello world hello war is upcoming"

You need to return:

{'hello': 2, 'world': 1, 'war': 1, 'is': 1, 'upcoming': 1}

Approach

  1. Split the sentence into words.
  2. Use a dictionary to count the number of times each word occurs.
  3. Optionally, convert all words to lowercase for case-insensitive calculations.

Solution in Python

def count_word_frequency(sentence):
    # Step 1: Convert to lowercase to avoid case mismatches
    sentence = sentence.lower()
    
    # Step 2: Split sentence into words
    words = sentence.split()
    
    # Step 3: Create an empty dictionary to hold word counts
    word_count = {}
    
    # Step 4: Count each word
    for word in words:
        if word in word_count:
            word_count[word] += 1  # Increment count if word already exists
        else:
            word_count[word] = 1   # Initialize count if word appears for the first time
    
    return word_count

# Example usage:
sentence = "Hello world hello"
result = count_word_frequency(sentence)
print(result)

Explanation

  1. sentence.lower(): Ensures "Hello" and "hello" are treated as the same.
  2. sentence.split(): Splits on whitespace by default.
  3. The dictionary word_count stores each word as a key and its count as a value.

Output:

{'hello': 2, 'world': 1, 'war': 1, 'is': 1, 'upcoming': 1}
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