Checking condition while Exception handling in python

Question

Aryan Kumar · Answer

Sure, here is how you can check a condition while exception handling in Python:

Python

def my_function():
  try:
    # This line might raise an exception
    1 / 0
  except ZeroDivisionError as e:
    # Check if the number is even
    if num % 2 == 0:
      print("The number is even.")
    else:
      print("The number is odd.")

In this example, the function my_function() tries to divide 1 by 0. If this division is successful, the try block will be executed. However, if the division fails, a ZeroDivisionError exception will be raised and the except block will be executed.

In the except block, we check if the number is even. If the number is even, we print the message "The number is even." Otherwise, we print the message "The number is odd."

Here is another example:

Python

def my_function():
  try:
    # This line might raise an exception
    num = int(input("Enter a number: "))
  except ValueError as e:
    print("Invalid input. Please enter a valid number.")
  else:
    # Check if the number is greater than 10
    if num > 10:
      print("The number is greater than 10.")
    else:
      print("The number is less than or equal to 10.")

In this example, the function my_function() asks the user to enter a number. The try block tries to convert the user input to an integer. If the conversion is successful, the try block will be executed. However, if the conversion fails, a ValueError exception will be raised and the except block will be executed.

In the except block, we print the message "Invalid input. Please enter a valid number." Otherwise, we check if the number is greater than 10. If the number is greater than 10, we print the message "The number is greater than 10." Otherwise, we print the message “The number is less than or equal to 10.”

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Checking condition while Exception handling in python

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