Implement a function to check if a given year is a leap year or not using Rust.

Question

Aryan Kumar · Answer

Sure, here is a Rust function to check if a given year is a leap year or not using Rust:

Rust

fn is_leap_year(year: i32) -> bool {
    if year % 400 == 0 {
        return true;
    } else if year % 100 == 0 {
        return false;
    } else if year % 4 == 0 {
        return true;
    } else {
        return false;
    }
}

fn main() {
    let year = 2020;
    let is_leap_year = is_leap_year(year);
    println!("The year {} is {}a leap year", year, if is_leap_year { "" } else { "not "));
}

This function first defines a function called is_leap_year that takes an i32 number as input and returns a bool value. The function checks if the year is a leap year by checking the following conditions:

If the year is divisible by 400, then the year is a leap year.
If the year is divisible by 100, but not by 400, then the year is not a leap year.
If the year is divisible by 4, but not by 100, then the year is a leap year.
Otherwise, the year is not a leap year.

The main function of the program then calls the is_leap_year function with the value 2020 as input. The result of the function call is then printed to the console.

To run the program, you can save it as a file called is_leap_year.rs and then compile it using the following command:

Code snippet

rustc is_leap_year.rs

Once the program is compiled, you can run it using the following command:

Code snippet

./is_leap_year

This will print the following output to the console:

Code snippet

The year 2020 is a leap year

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Implement a function to check if a given year is a leap year or not using Rust.

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