Swap Two integers variable values without using the third variable.

Question

Aryan Kumar · Answer

Sure, here is a C# code that swaps two integers without using a third variable:

C#

using System;

public class SwapExample
{
    public static void Main(string[] args)
    {
        int x = 10;
        int y = 20;

        // Swap x and y without using a third variable.
        x = x + y;
        y = x - y;
        x = x - y;

        Console.WriteLine("x = {0}, y = {1}", x, y);
    }
}

This code works by adding x and y together, then storing the result in x. Then, it subtracts y from the result, and stores the result in y. Finally, it subtracts x from the result, and stores the result in x. This effectively swaps the values of x and y without using a third variable.

Here is an explanation of how the code works:

The using System; statement imports the System namespace, which contains the Console class.
The public class SwapExample statement defines a class called SwapExample.
The public static void Main(string[] args) statement defines a method called Main that is the entry point for the program.
The int x = 10; statement declares an integer variable called x and initializes it to 10.
The int y = 20; statement declares an integer variable called y and initializes it to 20.
The x = x + y; statement adds y to x and stores the result in x.
The y = x - y; statement subtracts y from x and stores the result in y.
The x = x - y; statement subtracts x from y and stores the result in x.
The Console.WriteLine("x = {0}, y = {1}", x, y); statement prints the values of x and y to the console.
The }``` statement closes theMain` method.
The }``` statement closes theSwapExample` class.

Ravi Vishwakarma · Answer

There is a simple C# program to swap to an integer without using a third variable.

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Swap Two integers variable values without using the third variable.

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