---
title: "Where is this exception caught and handled?"  
description: "Where is this exception caught and handled?"  
author: "Revati S Misra"  
published: 2023-07-28  
updated: 2023-07-29  
canonical: https://www.mindstick.com/forum/159347/where-is-this-exception-caught-and-handled  
category: "java"  
tags: ["exception handling", "exception"]  
reading_time: 1 minute  

---

# Where is this exception caught and handled?

Where is this [exception](https://www.mindstick.com/articles/1824/objective-c-exception-handling) caught and handled?

## Replies

### Reply by Aryan Kumar

The exception in the code snippet below is caught and handled in the `catch` block that is declared for `ArithmeticException`.

```plaintext
public class ExceptionHandling {

  public static void main(String[] args) {
    try {
      int x = 10;
      int y = 0;
      int z = x / y;
    } catch (ArithmeticException e) {
      System.out.println("Division by zero");
    }
  }
}
```

The `try` block contains the code that could potentially throw an exception. In this case, the code that could throw an exception is the `int z = x / y;` statement. If the `y` variable is equal to 0, then the `ArithmeticException` exception will be thrown.

The `catch` block is declared for the `ArithmeticException` exception. This means that if the `ArithmeticException` exception is thrown, the `catch` block will be executed. The `catch` block will then print the message "Division by zero".

If the `y` variable is not equal to 0, then the `ArithmeticException` exception will not be thrown. In this case, the `try` block will execute normally and the `catch` block will not be executed.


---

Original Source: https://www.mindstick.com/forum/159347/where-is-this-exception-caught-and-handled

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