---
title: "How to handle the NumberFormatException in Java?"  
description: "How to handle the NumberFormatException in Java?"  
author: "Steilla Mitchel"  
published: 2023-07-23  
updated: 2023-07-23  
canonical: https://www.mindstick.com/forum/159246/how-to-handle-the-numberformatexception-in-java  
category: "java"  
tags: ["exception handling", "java", "exception"]  
reading_time: 2 minutes  

---

# How to handle the NumberFormatException in Java?

How do you [handle](https://www.mindstick.com/articles/311004/suede-skillet-handle-cover) the NumberFormatException in [Java](https://www.mindstick.com/articles/12214/web-development-company-in-india-laid-on-the-foundation-of-concrete-java-programming)?

## Replies

### Reply by Aryan Kumar

The NumberFormatException is an unchecked exception that is thrown when an attempt is made to convert a string with an incorrect format to a numeric value. This exception can occur for a number of reasons, such as if the string contains non-numeric characters, if the string is empty, or if the string does not represent a number of the specified type.

To handle the NumberFormatException, you can use the try-catch block. The try-catch block is a construct that allows you to execute a block of code and then catch any exceptions that are thrown. The general syntax for the try-catch block is as follows:

```plaintext
try {
  // Code that may throw an exception
} catch (NumberFormatException e) {
  // Handle the NumberFormatException
}
```

In the example above, the try block contains the code that may throw the NumberFormatException. If the NumberFormatException is thrown, it will be caught by the catch block. The catch block can then be used to handle the exception.

Here is an example of how to use the try-catch block to handle the NumberFormatException:

```plaintext
public class NumberFormatExceptionExample {

  public static void main(String[] args) {
    String str = "abc";

    try {
      int number = Integer.parseInt(str);
    } catch (NumberFormatException e) {
      System.out.println("The string \"" + str + "\" is not a valid number");
    }
  }
}
```

In this example, the str variable is assigned the value "abc". The Integer.parseInt() method is then used to try to convert the str variable to an integer. However, the str variable does not contain a valid number, so the NumberFormatException is thrown. The catch block then prints a message to the console indicating that the string "abc" is not a valid number.

Here are some other ways to handle the NumberFormatException:

- You can throw the exception to the caller of the method.
- You can log the exception to a file or database.
- You can terminate the program.

The best way to handle the NumberFormatException will depend on the specific requirements of your application.


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Original Source: https://www.mindstick.com/forum/159246/how-to-handle-the-numberformatexception-in-java

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