---
title: "mvc upload file with model - second parameter posted file is null"
description: "mvc upload file with model - second parameter posted file is null"
author: "Anonymous User"
published: 2014-12-09
updated: 2014-12-10
canonical: https://www.mindstick.com/forum/12777/mvc-upload-file-with-model-second-parameter-posted-file-is-null
category: "asp.net"
tags: ["c#", "mvc4", "model"]
reading_time: 2 minutes
---
# mvc upload file with model - second parameter posted file is null
I have a [simple](https://yourviews.mindstick.com/story/1469/5-simple-ways-to-stay-fit-amp-healthy) [model](https://yourviews.mindstick.com/view/81334/america-is-reopening-after-corona-lockdown-but-on-swedish-model) with 1 [string property](https://www.mindstick.com/forum/160244/how-to-use-stringlength-to-limit-the-length-of-a-string-property-in-a-model) which I [render](https://www.mindstick.com/interview/2205/why-we-need-a-separate-mobile-project-template-while-we-can-render-our-web-application-in-mobile-what-s-new-in-mvc-4-mobile-template) on a simple view.
the view looks like the following:
```
@using (Html.BeginForm("UploadFile","Home", FormMethod.Post, new {
encType="multipart/form-data" })){ @Html.TextBoxFor(m=> m.FirstName)
}
```
[Controller](https://www.mindstick.com/blog/273/passing-values-from-controller-to-view-in-asp-dot-net-mvc) is this:
```
[HttpPost]public ActionResult UploadFile(UploadFileModel model, HttpPostedFileBase file){ // DO Stuff return View(model);}
```
Now, when I submit, the model DOES get populated but the [second](https://answers.mindstick.com/qa/41761/how-did-the-second-industrial-revolution-influence-women-s-roles-in-society) [parameter](https://www.mindstick.com/blog/450/parameter-class-in-c-sharp) being HttpPostedFileBase is null. However when doing [Request](https://www.mindstick.com/blog/255/post-get-and-request-function-in-php).Files - it does seem to show there is a file in the Request being posted. How can I actually get the second parameter to bind?
## Replies
### Reply by Anonymous User
Why not add the uploaded files to your model like this:
```
public class UploadFileModel { public UploadFileModel() { Files = new List(); } public List Files { get; set; } public string FirstName { get; set; } // Rest of model details}
```
Then change your view to this:
```
@using (Html.BeginForm("UploadFile","Home", FormMethod.Post, new {
encType="multipart/form-data" })){ @Html.TextBoxFor(m=> m.FirstName)
@Html.TextBoxFor(m=> m.Files.Files, new { type = "file", name = "Files"
})