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Make a post to URL and get the response

Anonymous User179303-Nov-2014

I try to post an XML file to the url and get the response back. I have this code to post. I am not really sure how to check if it is posting correctly and how to get the response.

WebRequest req =null;WebResponse rsp =null;// try// {string fileName =@"C:\ApplicantApproved.xml";string uri ="http://stage.test.com/partners/wp/ajax/consumeXML.php"; req =WebRequest.Create(uri); req.Method="POST";// Post method req.ContentType="text/xml; encoding='utf-8'";// Wrap the request stream with a text-based writerStreamWriter writer =newStreamWriter(req.GetRequestStream());// Write the XML text into the stream writer.WriteLine(this.GetTextFromXMLFile(fileName)); writer.Close();// Send the data to the webserver rsp = req.GetResponse();

I think I should have the response in rsp but I am not seeing anything usufull on it.

asp.netc# http post 
Updated on 03-Nov-2014
Anonymous User

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1 Answers

Lillian Martin

Lillian Martin

03-Nov-2014
Please try following.
WebRequest req =null;string fileName =@"C:\ApplicantApproved.xml";string uri ="http://stage.test.com/partners/wp/ajax/consumeXML.php"; req =WebRequest.Create(uri); req.Method="POST";// Post method req.ContentType="text/xml; encoding='utf-8'";// Write the XML text into the streambyte[] byteArray =Encoding.UTF8.GetBytes(this.GetTextFromXMLFile(fileName));// Set the ContentLength property of the WebRequest. req.ContentLength= byteArray.Length;// Get the request stream.Stream dataStream = req.GetRequestStream();// Write the data to the request stream. dataStream.Write(byteArray,0, byteArray.Length);// Close the Stream object. dataStream.Close();WebResponse response = req.GetResponse();// Display the status.Console.WriteLine(((HttpWebResponse)response).StatusDescription);// Get the stream containing content returned by the server. dataStream = response.GetResponseStream();// Open the stream using a StreamReader for easy access.StreamReader reader =newStreamReader(dataStream);// Read the content.string responseFromServer = reader.ReadToEnd();// Display the content.Console.WriteLine(responseFromServer);// Clean up the streams. reader.Close(); dataStream.Close(); response.Close();


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