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How to get .outerHeight of element if visible

Anonymous User160401-Feb-2015

Im woundering if its possible to get .outerHeight() of element only if its is visible

I currently have

var $viewItem = $('.test').find('.item');

 

var viewItemHeight = $viewItem.outerHeight(true);

The problem is $viewItem

Will return two elements at a time, one will be hidden. If is possible to test and only get the height of the visible one ?


Updated on 01-Feb-2015
I am a content writter !

Can you answer this question?


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